Conditional probability | Statistics | American Public University

Example

Let’s look at a standard deck of 52 cards.

What is the probability of getting 2 kings assuming that the first one is not replaced?

4/52 * 3/51 = 1/13*1/17= 1/221

What is the probability of getting 2 kings assuming that the first one is replaced?

4/52 * 4/52 = 1/13 * 1/13 = 1/169

Instructions

Now for your main post do a similar problem using with replacement and without replacement. You can use a card problem as long as it is not 2 kings. Try your best to be original. Do not solve your own problems. Leave them for your classmates to work.